?S2.5?10km/h=4.17(102-2.52)/17.32=23m
?t10?2.52.5?10 =
2?17.32=0.22min
V:10?20km/h vp=15km/h 对应cp=15.94N/KN
?S10?20km/h=4.17(202-102)/15.94=78m ??S=101m
?t20?1010?20 =2?15.94=0.31min ??t=0.53min
V:20?30km/h vp=25km/h 对应cp=14.83N/KN
?S20?30km/h=4.17(302-202)/14.83=141m ??S=242m
?t30?2020?30 =
2?14.83=0.34min ??t=0.87min
V:30?40km/h vp=35km/h 对应cp=14.16N/KN
?S30?40km/h=4.17(402-302)/14.16=206m ??S=448m
?t40?3030?40 =
2?14.16=0.35min ??t=1.22min
V:40?47km/h vp=43.5km/h 对应cp=13.80N/KN
?S40?47km/h=4.17(472-402)/13.80=184m ??S=632m
?t?4040?47 =
472?13.8=0.25min ??t=1.47min
V:47?48km/h vp=47.5km/h 对应cp=12.67N/KN
?S47?48km/h=4.17(482-472)/12.67=31m ??S=663m
?t48?4747?48 =2?12.67=0.04min ??t=1.51min
V:48?50km/h vp=49km/h 对应cp=11.69N/KN
?S48?50km/h=4.17(502-482)/11.69=70m ??S=733m
?t50?4848?50 =
2?11.69=0.09min ??t=1.60min
此时快要出坡须试凑
V:50?52km/h vp=51km/h 对应cp=11.10N/KN
7
?S50?52km/h=4.17(522-502)/11.10=77m ??S=810m
52?50=0.09min ??t=1.69min
2?11.10 误差10m 可以接受试凑成功 进入下一坡段 ?t50?52 =
第二坡段 ij=-1.07,L=1100m,牵引
V:52?60km/h v
p=56km/h 对应cp=9.87+1.07=10.85N/KN
?S52?60km/h=4.17(602-522)/10.85=344m ??S=354m
?t52?60 =
60?52=0.37min ??t=2.06min
2?10.85 V:60?66km/h vp=63km/h 对应cp=8.38+1.07=9.45N/KN
?S60?66km/h=4.17(662-602)/9.45=334m ??S=688m
?t60?66 =
66?60=0.32min ??t=2.38min
2?9.45V:66?70km/h vp=68km/h 对应cp=7.11+1.07=8.18N/KN
?S66?70km/h=4.17(702-662)/8.18=277m ??S=965m
70?66=0.24min ??t=2.62min
2?8.18 此时还差135m，需要试凑，假设 ?t66?70 =
V:70?72km/h vp=71km/h 对应cp=6.05+1.07=7.12N/KN
?S70?72km/h=4.17(722-702)/7.12=166m ??S=1135m
72?70=0.14min ??t=2.76min
2?7.12误差31m，可以接受，试凑成功，进入下一坡段
第三坡段 ij=12,L=1000m,牵引
?t70?72 =
V:72?70km/h vp=71km/h 对应cp=6.05-12=-5.95N/KN
?S72?70km/h=4.17(702-722)/（-5.95）=199m ??S=230m
?t72?70 =
70?72=0.17min ??t=2.93min
2?(?5.95) 7
V:70?66km/h vp=68km/h 对应cp=7.11-12=-4.89N/KN
?S70?66km/h=4.17(662-702)/（-4.89）=464m ??S=694m
?t70?66 =
66?70=0.41min ??t=3.34min
2?(?4.89)此时还差306m，需要试凑，假设
V:66?64km/h vp=65km/h 对应cp=8.10-12=-3.90N/KN
?S66?64km/h=4.17(642-662)/（-3.90）=278m ??S=972m
?t66?64 =
误差28m，可以接受，试凑成功，进入下一坡段
第四坡段 ij=-1.30,L=2900m,继续牵引
V:64?66km/h vp=68km/h 对应cp=8.10+1.30=9.40N/KN
64?66=0.26min ??t=3.60min
2?(?3.90)?S64?66km/h=4.17(662-642)/9.40=115m ??S=87m
?t64?66 =
66?64=0.11min ??t=3.71min
2?9.40 V:66?70km/h vp=68km/h 对应cp=7.11+1.30=8.41N/KN
?S66?70km/h=4.17(702-662)/8.41=270m ??S=357m
?t66?70 =
70?66=0.24min ??t=3.95min
2?8.41 V:70?80km/h vp=75km/h 对应cp=4.81+1.30=6.11N/KN
?S70?80km/h=4.17(802-702)/6.11=1024m ??S=1381m
?t70?80 =
80?70=0.82min ??t=4.77min
2?6.11
此时还差1519m，可能要出坡，需要试凑，假设
V:80?88km/h vp=84km/h 对应cp=3.02+1.30=4.32N/KN
7
?S80?88km/h=4.17(882-802)/4.32=1297m ??S=2678m 继续试凑，假设
V:80?89km/h vp=84.5km/h 对应cp=2.92+1.30=4.22N/KN
?S80?89km/h=4.17(892-802)/4.22=1503m ??S=2884m
89?80=1.07min ??t=5.84min
2?4.22 误差16m，可以接受，试凑成功，进入下一坡段 第五坡段（限制坡道） ij=10.5,L=2800m,继续牵引
?t80?89 =
V:89?80km/h vp=84.5km/h 对应cp=2.92-10.5=-7.58N/KN
?S89?80km/h=4.17(802-892)/（-7.58）=837m ??S=821m
?t89?80 =
80?89=0.59min ??t=6.43min
2?(?7.58)V:80?70km/h vp=75km/h 对应cp=4.81-10.5=-5.69N/KN
（-5.69）=1099m ??S=1920m ?S80?70km/h=4.17(702-802)/
?t80?70 =
70?80=0.88min ??t=7.31min
2?(?5.69) V:70?66km/h vp=68km/h 对应cp=7.10-10.5=-3.4N/KN
?S70?66km/h=4.17(662-702)/（-3.4）=667m ??S=2587m
?t70?66 =
66?70=0.59min ??t=7.90min
2?(?3.4) 此时还差213m，需要试凑，假设
V:66?64km/h vp=65km/h 对应cp=8.10-10.5=-2.4N/KN
?S66?64km/h=4.17(642-662)/（-2.4）=438m 超出，继续试凑
V:66?65km/h vp=65.5km/h 对应cp=8.03-10.5=-2.47N/KN
7
?S66?65km/h=4.17(652-662)/（-2.47）=221m ??S=2808m
?t66?65 =
65?66=0.20min ??t=8.10min
2?(?2.47) 误差8m，可以接受，试凑成功，进入下一坡段 第六坡段 ij=-3.93,L=600m,继续牵引
V:65?66km/h vp=65.5km/h 对应cp=8.03+3.93=11.96N/KN
?S65?66km/h=4.17(662-652)/11.96=46m ??S=54m
?t65?66 =
66?65=0.04min ??t=8.14min
2?11.96 V:66?70km/h vp=68km/h 对应cp=7.10+3.93=11.03N/KN
?S66?70km/h=4.17(702-662)/11.03=206m ??S=260m
70?66=0.18min ??t=8.32min
2?11.03 此时还差340m，即将出坡，需要试凑，假设 ?t66?70 =
V:70?74km/h vp=72km/h 对应cp=5.67+3.93=9.6N/KN
?S70?74km/h=4.17(742-602)/9.6=250m ??S=510m 没有出坡，继续试凑
V:70?75km/h vp=72.5km/h 对应cp=5.52+3.93=9.45N/KN
?S70?75km/h=4.17(752-702)/9.45=320m ??S=580m
75?70=0.26min ??t=8.58min
2?9.45 误差20m，可以接受，认为试凑成功，进入下一坡段
第七坡段 ij=3.12,L=2300m,因下一坡段要通过车站，考虑到限速问题，于是计
划先牵引一段后进行惰行缓冲最后必要时可能要制动一段距离
?t70?75 = 牵引
V:75?77km/h vp=76km/h 对应cp=4.52-3.12=1.4N/KN
?S75?77km/h=4.17(772-752)/1.4=906m ??S=886m
?t75?77 = 考虑惰行
7
77?75=0.71min ??t=9.29min 2?1.4
机车牵引力计算路段设计与分析报告
