> newdata=(x1=5200,x2=2000,x3=1100,x4=1000,x5=1300,x6=45000,x7=34000,x8=,x9= > predict(dy,newdata,interval=\ fit lwr upr 1 >
R语言代码试题答案步骤
>newdata=(x1=5200,x2=2000,x3=1100,x4=1000,x5=1300,x6=45000,x7=34000,x8=,x9=>predict(dy,newdata,interval=\fitlwrupr1>
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