军队文职数学2模拟题及答案解析C.?
?11?
?01??D.??
01?
?10??
21.【答案】B2
【解析】由??12???01??????2
?1??0?2?2???
00?1??????10?
?01?。故选B。?a11?xa12?xa13?xa14?x22.设f?x??a21?2xa22?2xa23?2xa24?2xa,则多项式f?x?可能的最高次数是31?3xa32?3xa33?3xa34?3xa41?4xa41?4xa43?4xa44?4x()A.0B.1C.2D.322.【答案】B【解析】利用行列式的性质对f?x?进行等量变换,再进行判断易于判断。a11?xa12?xa13?xa14?xa11?xa12?xa13?xa14?xf?x??a21?2xa22?2xa23?2xa24?2xa21?2a11a22?2a12a23?2a13a24?2a14aa32?3xa33?3xa34?3x?a31?3a11a32?3a12a33?3a13a?31?3x34?3a14a41?4xa41?4xa43?4xa44?4xa41?4a11a41?4a12a43?4a13a44?4a14a11a12a13a14xxxxa21?2a11a22?2a12a23?2a13a24?2a14?a21?2a11a22?2a12a23?2a13a24?2a14a31?3a11a32?3a12a33?3a13aa31?3a11a,故34?3a1432?3a12a33?3a13a34?3a14a41?4a11a41?4a12a43?4a13a44?4a14a41?4a11a41?4a12a43?4a13a44?4a14f?x?的可能的最高次数为1次。故选B。??1
1
1
1?23.设A=?
0
1?1a?
?3a4??
,若r?A*
??1,则a?()?2?3
519?
?
16军队文职数学2模拟题及答案解析A.1B.3C.1或3D.无法确定23.【答案】C【解析】由r?A*??1,得r?A??3
,则A?0
,即111111110?
01?1a
?1a23a4?
0100a?1
2?a
??a?1??6?2a?,得a?1或3,且此时均满足35
1
900
0
6?2a
r?A??3,故选C。17