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SQL数据库面试题以及答案

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Student(S#,Sname,Sage,Ssex)学生表 S#:学号 Sname:学生姓名 Sage:学生年龄 Ssex:学生性别

Course(C#,Cname,T#)课程表 C#:课程编号 Cname:课程名称 T#:教师编号

SC(S#,C#,score)成绩表 S#:学号 C#:课程编号 score:成绩

Teacher(T#,Tname)教师表 T#:教师编号: Tname:教师名字

问题:

1、查询“001”课程比“002”课程成绩高的所有学生的学号

select a.S# from (select S#,score from SC where C#='001')a, (select s#,score from SC where c#='002')b Where a.score>b.score and a.s# = b.s#;

2、查询平均成绩大于60分的同学的学号和平均成绩

select S#, avg(score) from sc group by S# having avg(score)>60

3、查询所有同学的学号、姓名、选课数、总成绩

select student.S#, student.Sname, count(sc.C#), sum(score) from student left outer join SC on student.S# = SC.S# group by Student.S#, Sname

4、查询姓‘李’的老师的个数:

select count(distinct(Tname)) from teacher

where tname like '李%';

5、查询没有学过“叶平”老师可的同学的学号、姓名:

select student.S#, student.Sname from Student

where S# not in (select distinct(SC.S#) from SC,Course,Teacher

where sc.c#=course.c# AND teacher.T#=course.T# AND Teahcer.Tname ='叶平');

6、查询学过“叶平”老师所教的所有课的同学的学号、姓名:

select S#,Sname from Student

where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平' group by S#

having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='叶平'));

7、查询学过“011”并且也学过编号“002”课程的同学的学号、姓名:

select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and

exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');

8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名:

Select S#,Sname

from (select Student.S#,Student.Sname,score ,

(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2

from Student,SC

where Student.S#=SC.S# and C#='001') S_2 where score2 < score;

9、查询所有课程成绩小于60的同学的学号、姓名:

select S#, sname from student where s# not in

(select student.s# from student, sc where s.s# = sc.s# and score>60);

10、查询没有学全所有课的同学的学号、姓名:

select student.s#, student.sname from student, sc

where student.s#=sc.s#

group by student.s#, student.sname

having count(c#)<(select count(c#) from course);

11、查询至少有一门课与学号为“1001”同学所学相同的同学的学号和姓名:

select s#, Sname from Student, SC

where student.s# = sc.s#

and c# in (select c# from SC where s#='1001');

12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名;

select distinct sc.s# , sname

from student, sc where student.s#=sc.s#

and c# in (select C# from sc where s#='001');

13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩:

Update Sc Set Score=(Select Avg(s2_Score) From sc s2 Where s2.c#=sc.c#) Where c# IN

(Select c# From sc cs INNER JOIN Teacher tc ON cs.t#=tc.t# WHERE tname ='叶平')

14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名:

select s# from sc where c# in (select c# from sc where s#='1002') group by s# having count(*)=

(select count(*) from sc where s#='1002');

15、删除学习“叶平”老师课的SC表记录:

delect sc

from course, Teacher where course.c#=sc.c# and course.t#=teacher.t# and tname='叶平';

16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、002号课的平均成绩:

Insert SC select S#,'002',

(Select avg(score) from SC where C#='002')

from Student where S# not in (Select S# from SC where C#='002');

17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示:学生ID,数据库,企业管理,英语,有效课程数,有效平均分:

select s# as 学生ID,

(select score from sc where sc.s#=t.s# and c#='004') as 数据库, (select score from sc where sc.s#=t.s# and c#='001') as 企业管理, (select score from sc where sc.s#=t.s# and c#='006') as 英语, count(*) as 有效课程数, avg(t.score) as 平局成绩 from sc as t group by s#

order by avg(t.score)

18、查询各科成绩最高和最低的分: 以如下的形式显示:课程ID,最高分,最低分

select L.c# as 课程ID, L.score as 最高分, R.score as 最低分 from sc L, sc R where L.c# = R.c#

and L.score = (select max(IL.score) from sc IL, student as IM where L.c#=IL.c# and IM.s#=IL.s# group by IL.c#)

and R.score = (select min(IR.score) from sc as IR where R.c#=IR.c# group by IR.c#);

SQL数据库面试题以及答案

Student(S#,Sname,Sage,Ssex)学生表S#:学号Sname:学生姓名Sage:学生年龄Ssex:学生性别Course(C#,Cname,T#)课程表C#:课程编号Cname:课程名称T#:教师编号SC(S#,C#,score)成绩表S#:学号C#:课程编号score:成绩Teacher(T#,Tname
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