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钢结构原理与设计第2版--课后答案

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4-1解:

12N??GNGK??QNQK?1.2??315?1.4??315?420kN

33焊缝质量为三级,用引弧板施焊。查表得E43焊条的ftW?185N/mm2,Q235钢的f?215N/mm2。

N420?103t?W??11.35mm bft200?185故取t?12mm。

4-2解:

N??GNGK??QNQK?1.2?0.2Nk?1.4?0.8Nk?1.36Nk

焊缝质量为二级,ftW?215N/mm2未用引弧板施焊

lW?400?2?12?376mm

ftW?N,N?ftWlWt?1.36Nk lWtftWlWt215?376?12Nk???713.3kN

1.361.36

4-4解:

1)焊脚尺寸hf

背部尺寸???hf1?1.5tmax?1.5?10?4.74mm

??hf1?1.2tmin?1.2?8?9.6mm??h?1.5tmax?1.5?10?4.74mm趾部尺寸?f2

????h?t?1~2?8?1~2?6~7mm??f2min为方便备料,取hf1?hf2?hf?6mm,满足上述要求。 2)轴心力N的设计值

N??GNGK??QNQK?1.2?0.1?180?1.4?0.9?180?248.4kN

按角钢背与趾部侧面角焊缝内力分配系数可知:等边角钢内力分配系数

e1e?0.3 2?0.7 bb对角钢趾部取力矩平衡得: N1b?Ne2

N1?e2N?0.3N?0.3?248.4?74.52kN bN2?N?N1?0.7N?0.7?248.4?173.88kN

3)焊缝长度。

当构件截面为一只角钢时,考虑角钢与节点板单面连接所引起的偏心影响, ftW应乘以折减系数0-85。

N174.52?103角钢趾:lW1???130mm?8hf?48mm

0.7hf?0.85ffW0.7?6?0.85?160取l1?140mm (130?2hf?142mm,取10mm的整数倍) 角钢背:lW2N2173.88?103???304mm?60hf?360mm W0.7hf?0.85ff0.7?6?0.85?160取l2?320mm (304?2hf?316mm,取10mm的整数)

4-5解:

腹板受到轴心拉力Nk作用

N??GNGK??QNQK?1.2?0.2?440?1.4?0.8?440?598.4kN

焊脚尺寸hf

hf?1.5tmax?5.6mm,

hf?tmin?(1~2)?8~9mm

N598.4?103取hf?6mm时,lW???445.2mm?60hf?360mm W2?0.7hfff2?0.7?6?160不可行;

取hf?7mm时,lw?381.6mm,lw?60hf?420mm 可行,l?381.6?2hf?395.6mm,取l?400mm 取hf?9mm时,lw?296.8mm,lw?60hf?540mm 可行,l?296.8?2hf?314.8mm,取l?320mm

故最小的焊脚尺寸可取7mm,钢板搭接长度为400mm 最大的焊脚尺寸可取9mm,钢板搭接长度为320mm

4-7解:

(1)直接计算法

M?Nl?50?0.2?10kN?m

M10?1061488.12 ?f???N/mm220.7hflW60.7hf?2406hf?N50?103297.6f?0.7hl??N/mm2

fW0.7hf?240hf?2??f??????2?fW??f?ff ?22?1488.1????297.6??1.22hf?????160 ???hf??解得:hf?7.85mm 采用h18?6.36mmf?8mm?1.5tmax?1.5??t?1~2??8~9mm,可

min?(2)试算法

h???1.5tmax?1.5?18?6.36mmf ??tmin??1~2??8~9mm取hf?8mm

AW?helW?0.7hflW?0.7?8?240?1344mm2 W?16hl21WeW?6?0.7?8?2402?53760mm3

M10?106?0.7h2?0.7?8?24026?186.0N/mm2f? flW6N50?103?f?0.7h?7?8?240?37.2N/mm2

flW0.?2??f??????2???186?2?37.22?156.9N/mm2?fW??f?f?1.22??f?160N/mm2,可故hf?8mm

4-8解:

R?1.2?25%Rk?1.4?75%Rk?405kN

l?300mm lh?80?10?70mm

取焊脚尺寸hf?6mm he?0.7hf?4.2mm (1)几何关系

水平焊缝计算长度lWh?lh?hf?70?6?64mm 全部焊缝计算长度lW?l?2lWh?300?2?64?428mm 全部焊缝有效截面AW?helW 形心位置x?略去he3项

223??hel3?l??0.42?30?30??Ix??2?helWh??????2??0.42?6.4?????2154.6cm4

1212?2???2????????2helWh?lWhAW2?2?he?6.4?6.42?0.96cm

he?42.823?helWh?lWh??Iy?2??helWh??x???helWhx2?2???12?? 23?0.42?6.4?6.4???2???0.42?6.4???0.96???0.42?6.4?0.962?47.8cm412?2?????焊缝有效截面对形心O的极惯性矩

I0?Ix?Iy?2154.6?47.8?2202.4cm4

(2)强度验算

Ra405?70.4?10?3R??14.3kN?m V??202.5kN a?80?x?70.4mm T?222x1?lWh?x?64?9.6?54.4mm y1?Tfl?150mm 2Tx114.3?106?54.4????35.3N/mm2? 4I02202.4?10Ty114.3?106?1502????97.4N/mm? 4I02202.4?10Tf

钢结构原理与设计第2版--课后答案

4-1解:12N??GNGK??QNQK?1.2??315?1.4??315?420kN33焊缝质量为三级,用引弧板施焊。查表得E43焊条的ftW?185N/mm2,Q235钢的f?215N/mm2。N420?103t?W??11.35mmbft200?185故取t?12mm。4-2解:N??GNGK?
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