所以2d?mx1?2y1?mx2?2y2m?42m? ?2?2y1?y2m?42?. 又因为y1?y2??y1?y2?222m2?1?4y1y2?,
m2?2m?所以2d?2?2y1?y2m?42??22m2?1m?42 所以四边形OAPB面积
22m2?131?221?2,其中m?R. S?OP?2d? 2m?42m?4可知当m?0时, Smin?2,即四边形OAPB面积的最小值为2.
高考数学玩转压轴题专题3_3图形面积求最值,函数值域正当时1
所以2d?mx1?2y1?mx2?2y2m?42m??2?2y1?y2m?42?.又因为y1?y2??y1?y2?222m2?1?4y1y2?,m2?2m?所以2d?2?2y1?y2m?42??22m2?1m?42所以四边形OAPB面积22m2?131?221?2,其中m?R.S?OP?2d?2m?42m?4可知当m?0时,Smin?2,即四边形O
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