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Adj2 Adj3 Adj4 Adj5 Adj6 -73 -77 -85 -90 -97 -75 0 -83 -94 -99 -74 -80 -87 -91 -98 -75 -79 -88 -90 -99 -76 -81 -84 -95 -96 -77 -79 0 -93 -97 -75 0 -86 -92 0 -77 -80 -87 -90 0 allAdjacentCellsAveraged=NO numberOfZeroResults=2
averagingWindowSizeAdjCell=8
(3) 服务小区对各邻区参数设置如下： Adj1 Adj2 Adj3 Adj4 Adj5 Adj6 SL -95 -95 -95 -95 -95 -95 LMRG PRI(Priority) OF(hoLoadFactor) 3 3 3 6 3 3 3 4 3 4 3 3 1 2 1 2 1 1 BLT(btsLoadThreshold) 80% 85% 85% 80% 75% 80% BTS load 85% 90% 70% 70% 70% 70% 请根据上述已知条件判断：
a) 什么时候，MS将触发切换
b) 候选目标小区的电平、优先级分别如何？ c) 最终的目标小区是哪个邻区？
d) Serving cell:
P1=(35*2+36*2+34*2)/(2+2+2)=35>20 P2=(36*2+34*2+32*1)/(2+2+1)> 20 P3=(34*2+32*1+25*1)/(2+1+1) >20 P4=(32*1+25*1+20*1)/(1+1+1)>20 ……
P6=(20*1+21*2+18*2)/(2+2+1)=19.6<20 P7=18.8<20
So MS will handover to the best adjacent cell while received the 9th sample, its level is -110+16=-94 Adjacent cell level: Adj1=(-65-67-71-69-….-71)/8=-69.8
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Adj2=(-73-75-74-….-77)/8=-75.3 Adj3=-79.4 Adj4=-85.8 Adj5=-91.9 Adj6=(-97-99-98-99-….-0)/6=-97.7 Adjacent cell priority: Adj1 and Adj2 are overloaded, so these 6 adjacent cell’s priority is:
P4> p3> p5> p6> p1> p2
Adj1=3-1=2 Adj2=4-2=2 Adj3=3 Adj4=4 Adj5=3 Adj6=3 Handover EQ1: The RX level of Adj1-Adj5 are all fit for the SL condition, except Adj6. Handover EQ2: LMRG=3: -94+3=-91 LMRG=6: -94+6=-88 So only Adj1, Adj2, Adj3,Adj4 is ok
Accord to the priority above, the best target cell is Adj4. 附：
1. Erlang B table
2. SDCCH信道配置策略
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一、 单项选择题
CCCDC CBABB
二、 多项选择题
1. EFGH 2. ABCDE 3. ABE 4. ABC 5. ABD 6. ABDEF 7. ABCFG 8. ABCDEF 9. ACDEF 10. DE
三、 填空题
1. DAC,CF
2. Um(Air),Abis,Ater,A 3. 4.615,120,480
4. ZTPI:MEAS,ZTPI:GPRS,ZEGO,ZWOI 5. CBDA
6. RNW,ALARM,MEASURMENT ADMIN,PLANNING DATA IMPORT/EXPORT 7.
ALARM,TRX QUALITY, TCH/SDCCH AVAILABLE
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四、 计算题
2. Coverage cells=40/0.5=80
Capacity cells=capacity requirement/capacity per cell=1600/28.3=56.54 capacity requirement =80000*80%*90/3600=1600 TRXs per cell=(15.6/0.2-3*6)/(3*5) +1 =5 capacity per cell=28.3erl so we need 80 new cells.
3. Path loss=33-4+4+16-3.5-(-104)=149.5
TX POWER-3-3.5+16-149.5-4=-102? TX POWER=-102-(-3-3.5+16-149.5-4)=42
4. Paging capacity=paging msg/paging block * paging block/s*3600
When AG=1, combined BCCH
Paging block/s=(3-1)/0.235=2/0.235 When AG=2, non-combined BCCH Paging block/s=(9-2)/0.235=7/0.235
And paging msg/paging block is not related with the parameters AG and BCCH type, So the answer is 7/2=350%
5. When TRX=1
Cell traffic=2.95erl Subs=2.95/0.025
Sdcch erl=sdcch erl/subs*subs=[(1.5*3+1*3+0.15*3+0.5*2)*2.95/0.025]/3600=0.29erl Refer to erlang B table: it need 3 sdcch sub channels
When TRX=6
Cell traffic=34.682erl Subs=34.682/0.025
Sdcch erl=sdcch erl/subs*subs=[(1.5*3+1*3+0.15*3+0.5*2)*34.682/0.025]/3600=3.41erl Refer to erlang B table: it need 8 sdcch sub channels
五、 简答题
1. Network planning process:
Preplanning?site selection/survey?frequency/adjacent cell/parameter planning?on air?evaluation and audit Daily optimization:
KPI target?find network problem(NMS,DT/CQT, end user complaint)?analysis problem?solution and change request?monitor and evaluation?record and report Intensive optimization: Network audit?KPI target?organization and operation?optimization
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activities?monitoring ?record and report 2. Physical adjust
Cell selection/reselection parameter optimization Cell handover parameter optimization Power related parameter Feature
Enhance device Etc.
3. Poor coverage
Paging related parameter setting(MSC、CCCH) Hardware faulty Interference
Network loading status Etc.
4. Cell selection/reselection parameter optimization
Physical adjust
Power related parameter Feature Expansion Etc. 5. NMS:
DCR/quality/HOF/blocking etc. DT: Coverage/quality/dcr/hof/CSSR etc. CQT: Cross talking/one way conversation/coverage etc.
六、 综合题
1. Reuse pattern: TRX cell number 1 45 2 45 3 40 4 25 5 16 6 13 7 11 8 8 total 203 Frequency plan: BCCH frequency needed 21 21 19 12 8 7 6 4 reuse pattern 3*7 3*6 3*5 3*4 3*3 3*3 rest TRX8 frequency number 21 18 15 12 9 9 10 94 TRX2 TRX3 TRX4 TRX5 TRX6 TRX7 .
3-GSM网络优化测试题-高级-done
