习题2-21 P108R2①Au= -gm(RD//RL) ?-22.5R?C1Ri= RG+ (R1//R2) ?20 MgR+o= RD=15 k?U?②不接C-iR1S 时，微变等效电路为GDRgU?gsR1R2SgmU?gsRdRLRsGDRgU?gsRgmU?gs1R2SRdRLRsU?i?U?gs?I?dRs?(1?gmRs)U?gsU?o??gmU?gs(Rd//RL)?AU?ogm(Rd//RL)u?U???i1?g??9mRsR+VdDDC2+RLU?RosCs-VDD=30VRd=15k?Rs=1k?Rg=20M?R1=30k?R2=200k?RL=1M?gm=1.5mSVDD=30VRd=15k?Rs=1k?Rg=20M?R1=30k?R2=200k?RL=1M?gm=1.5mS
习题2-22 P109RguIVGGRsIDuOVDDUGS(th)=2VIDO=2mAVDD=20VVGG=4VRs=4.7k?Rg=1M?UGSQ?VGG?IDQRs2?UGSQ?IDQ?0.27mAIDQ?IDO??1??U??GS(th)?2gm?IDOIDQ?0.735mSUGS(th)UGSQ?2.73V微变等效电路GSuI?gmUgsDRSuo??gU?UomgsRs??U??U??(1?gR)U?Uigsomsgs?UgmRso?Au???0.776?Ui1?gmRsUGS(th)=2VIDO=2mAVDD=20VVGG=4VRs=4.7k?Rg=1M?
习题2-23 P109Rb1C1Rc1VT1VCC?UBEQ解：①设UBEQ1=UBEQ2=0.7，?IBQ1?RbICQ1??1IBQ1?2mA?0.04mARc2+VCCVT2Re2uIuO设IBQ2< 习题2-24 P109Rc1Re2VT1Rc2VT2+VCC?1=40?2=20uSRbRiuO-VEE解：①uS=0时，uC2=uO=0ICQ2?VEE/Rc2?3.64mAIBQ2?ICQ2/?2?0.18mAIEQ2?IBQ2?ICQ2?3.82mAUEQ2?VCC?IEQ2RVe2?4.36UBEQ1=0.7V|UBEQ2|=0.7VVCC=12VVEE=12VRc1=3.9k?Rc2=3.3k?Re2=2k?Rb=200k?UCQ1?UBQ2?UEQ2?UBEQ2?3.66VRc1Re2VT1Rc2VT2+VCC?1=40?2=20uSRbuO-VEEIRC1?(VCC?UCQ1)/Rc1?2.14mAICQ1?IRC1?IBQ2?2.32mAIBQ1?ICQ1/?1?0.058mAUBEQ1=0.7V|UBEQ2|=0.7VVCC=12VVEE=12VRc1=3.9k?Rc2=3.3k?Re2=2k?Rb=200k?IEQ1?ICQ1?IBQ1?2.38mAUEQ1??VEE??12V，UBQ1??11.3V Rc1Re2VT1Rc2Ri2VT2+VCC?1=40?2=20uSRbRiuO②rbe1?300?(1??1)26?748?IEQ1-VEERc1=3.9k?Rc2=3.3k?Re2=2k?Rb=200k?IEQ1=2.38mAIEQ2=3.82mArbe2?300?(1??2)26?443?IEQ2Ri?Ri1?rbe1?748?，Ro?Rc2?3.3k?Ri2?rbe2?(1??2)Re2?42.443k?Rc1Re2+VCCVT2uSuiRbRiuc1VT1Rc2Ri2?1=40?2=20uO-VEERc1=3.9k?Rc2=3.3k?Ri1=748?Ri2=42.443k?rbe1=748?uc1?1(Rc1//Ri2)Au1?????191uirbe1uo?2Rc2Au2?????1.56uc1Ri2Au?Au1?Au2?297
模拟电子技术基础简明教程杨素行(第三版)
