经济数学基础形成性考核册及参考答案
作业(一)
(一)填空题 1.limx?0x?sinx?___________________.答案:0 x?x2?1,x?02.设f(x)??,在x?0处连续,则k?________.答案:1 ?k,x?0?3.曲线y?x在(1,1)的切线方程是 .答案:y?211x? 224.设函数f(x?1)?x?2x?5,则f?(x)?____________.答案:2x 5.设f(x)?xsinx,则f??()?__________.答案:?(二)单项选择题 1. 函数y?π2π 2x?1的连续区间是( )答案:D 2x?x?2A.(??,1)?(1,??) B.(??,?2)?(?2,??)
C.(??,?2)?(?2,1)?(1,??) D.(??,?2)?(?2,??)或(??,1)?(1,??) 2. 下列极限计算正确的是( )答案:B A.limxxx?0?1 B.lim?x?0xx?1
C.limxsinx?01sinx?1 D.lim?1
x??xx3. 设y?lg2x,则dy?( ).答案:B A.
11ln101dx B.dx C.dx D.dx 2xxln10xx4. 若函数f (x)在点x0处可导,则( )是错误的.答案:B
A.函数f (x)在点x0处有定义 B.limf(x)?A,但A?f(x0)
x?x0 C.函数f (x)在点x0处连续 D.函数f (x)在点x0处可微 5.当x?0时,下列变量是无穷小量的是( ). 答案:C A.2 B.(三)解答题 1.计算极限
xsinx C.ln(1?x) D.cosx xx2?3x?21(x?2)(x?1)x?2??(1)lim = = limlim2x?1x?1x?1x?12(x?1)(x?1)(x?1)
1
x2?5x?61(x?2)(x?3)x?3(2)lim2=lim = lim =
x?2x?6x?8x?2(x?2)(x?4)x?2(x?4)2(3)limx?0(1?x?1)(1?x?1)1?x?1=lim x?0xx(1?x?1) =limx?0?x?11=lim??
2x(1?x?1)x?0(1?x?1)1?35?2x2?3x?5xx?1 ?lim(4)limx??3x2?2x?4x??2433??2xx(5)lim5xsin3x33sin3x?lim= x?03xsin5x5x?0sin5x5x2?4(x?2)(x?2)(6)lim?lim?4
x?2sin(x?2)x?2sin(x?2)
1?xsin?b,x?0?x?2.设函数f(x)??a,x?0,
?sinxx?0?x?问:(1)当a,b为何值时,f(x)在x?0处有极限存在? (2)当a,b为何值时,f(x)在x?0处连续.
答案:(1)当b?1,a任意时,f(x)在x?0处有极限存在; (2)当a?b?1时,f(x)在x?0处连续。 3.计算下列函数的导数或微分: (1)y?x?2?log2x?2,求y? 答案:y??2x?2ln2?(2)y?x2x21 xln2ax?b,求y?
cx?d答案:y?=
a(cx?d)?c(ax?b)ad?cb ?22(cx?d)(cx?d)2
(3)y?13x?5,求y?
11答案:y?23x?5=(3x?5)? y???32(3x?5)3
(4)y?x?xex,求y?
答案:y??12x?(x?1)ex
(5)y?eaxsinbx,求dy
答案:y??(eax)?sinbx?eax(sinbx)?
?aeaxsinbx?eaxcosbx?b
?eax(asinbx?bcosbx) dy?eax(asinbx?bcosbx)dx
1(6)y?ex?xx,求dy
答案:dy?(32x?11x2ex)dx (7)y?cosx?e?x2,求dy 答案:dy?(2xe?x2?sinx2x)dx
(8)y?sinnx?sinnx,求y? 答案:y?=nsinn?1xcosx+cosnxn=n(sinn?1xcosx?cosnx)
(9)y?ln(x?1?x2),求y? 答
案
y??1(x?1?x2)??112?12x?1?x2x?1?x2(1?2(1?x)2x)?11?x2
3(10)y?2cot1x?1?x2?2xx,求y?
3
:
?1xx?1?x2(1?1?x2)