解一元二次方程之十字相乘法专项练习题

relationship, established equivalent relationship 14, and subject: application problem (4)--scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units \hen in-line solution. Category fraction multiplication word problem score Division applications engineering problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significance in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly used time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)--line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry preliminary knowledge (2)--plane graphics review content triangle, and edges shaped, and round, and fan axisymmetric graphics perimeter and area combination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cylinder and cone 2, column is divided into: cuboid, square 3, cone cone of the features of cuboids and cubes relationship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table ...和解一元二次方程十字相乘法专项练习题

(1) a2－7a+6=0； (2)8x2+6x－35=0；

(3)18x2－21x+5=0； (4) 20－9y－20y2=0；

(5)2x2+3x+1=0；

(7)6x2－13x+6=0；

(9)6x2－11x+3=0；

(11)10x2－21x+2=0；

(13)4n2+4n－15=0；

(15)5x2－8x－13=0；

(17)15x2+x－2=0；

(19) 2(a+b) 2+(a+b)(a－b)－6(a－b) 2=0；

(6)2y2+y－6=0； (8)3a2－7a－6=0； (10)4m2+8m+3=0； (12)8m2－22m+15=0； (14)6a2+a－35=0； (16)4x2+15x+9=0； (18)6y2+19y+10=0； (20)7(x－1) 2+4(x－1)－20=0

relationship, established equivalent relationship 14, and subject: application problem (4)--scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units \hen in-line solution. Category fraction multiplication word problem score Division applications engineering problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significance in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly used time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)--line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry preliminary knowledge (2)--plane graphics review content triangle, and edges shaped, and round, and fan axisymmetric graphics perimeter and area combination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cylinder and cone 2, column is divided into: cuboid, square 3, cone cone of the features of cuboids and cubes relationship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table ...和参考答案： (1)(a-6)(a-1)， (3)(3x-1)(6x-5)， (5)(x+1)(2x+1)， (7)(2x-3)(3x-2)， (9)(2x-3)(3x-1)， (11)(x-2)(10x-1)， (13)(2n+5)(2n-3)， (15)(x+1)(5x-13)， (17)(3x-1)(5x=2)， (19)(3a-b)(5b-a)，

(2)(2x+5)(4x-7) (4)-(4y-5)(5y+4) (6)(y+2)(2y-3) (8)(a-3)(3a+2) (10)(2m+1)(2m+3) (12)(2m-3)(4m-5) (14)(2a+5)(3a-7) (16)(x+3)(4x+3) (18)(2y+5)(3y+2) (20)(x+1)(7x-17)

解一元二次方程十字相乘法专项练习题 9.21

一、十字相乘分解因式：

分解因式：x2?3x?2 x2?3x?2 x2?2x?3 x2?2x?3 x2?5x?6 x2?5x?6 x2?5x?6 x2?5x?6

x2?x?2 x2?4x?12 x2?2x?63 x2?8x?15

x2?12x?32 x2?10x?9 x2?3x?10 x2?2x?15

分解因式： 2x2?5x?2 2x2?5x?3 2x2?3x?20 2x2?5x?7

2x2?7x?3

2x2?7x?3

2x2?7x?6

2x2?7x?6

3x2?7x?6

3x2?8x?3

3x2?5x?2

5x2?3x?2

5x2?6x?8 6x2?5x?25 6x2?7x?3

relationship, established equivalent relationship 14, and subject: application problem (4)--scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units \hen in-line solution. Category fraction multiplication word problem score Division applications engineering problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significance in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly used time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)--line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry preliminary knowledge (2)--plane graphics review content triangle, and edges shaped, and round, and fan axisymmetric graphics perimeter and area combination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cylinder and cone 2, column is divided into: cuboid, square 3, cone cone of the features of cuboids and cubes relationship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table ...和学乐教育数学

分解因式： x2?x??a2?a? x3?4x2?21x 3x3?10x2?3x

x4?6x2?27 x4?10x2?9

(2x?3)2?3(2x?3)?2 (x2?8x)2?22(x2?8x)?120

二、用因式分解法解下列方程

(1) a2－7a+6=0； (2)8x2+6x－35=0；

(3)18x2－21x+5=0； (4) 20－9y－20y2=0； (5)2x2+3x+1=0； (6)2y2+y－6=0；

(7)6x2－13x+6=0； (8)3a2－7a－6=0；

(9)6x2－11x+3=0； (10)4m2+8m+3=0；

(11)10x2－21x+2=0； (12)8m2－22m+15=0；