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二次函数动点问题解答方法技巧(含例解答案)

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3?0???b

23b?

233?BC的解析式为y??x? ··································································· 2分

4232?y??x?3?x1??1???4(2)由?,得?9

y1??y??3x?3??4??429??0) ?C??1,?,B(2,4???x2?2 ············································· 4分 ??y2?09 ·················································································· 5分 4199?S△ABC??4?? ············································································· 6分

242(3)过点N作NP?MB于点P EO?MB ?NP∥EO

?△BNP∽△BEO ·················································································· 7分 BNNP?? ··························································································· 8分 BEEO?AB?4,CD?由直线y??33?3?x?可得:E?0,? 42?2?53,则BE?

22?在△BEO中,BO?2,EO??62tNP,?NP?t ··········································································· 9分 ?5352216?S?t(4?t)

25312S??t2?t(0?t?4) ········································································ 10分

55312S??(t?2)2? ················································································ 11分

5512此抛物线开口向下,?当t?2时,S最大?

512······················ 12分 ?当点M运动2秒时,△MNB的面积达到最大,最大为. ·5

二次函数动点问题解答方法技巧(含例解答案)

3?0???b23b?233?BC的解析式为y??x?···································································2分4232?y??x?3?x1??1???4(2)由?,得?9y1??y??3x?3??4??429??0)?C??
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