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化工课程设计 - 图文 

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??01=

⑵提馏段:

????11.72508

==10.52??╱?? ??00.164??02=

????21.82151

==11.11??╱?? ??00.1644.4流体力学核算

(1)塔板压降

1.精馏段 ⑴干板阻力 因为Φ≤15%,

????=

查图得:C0=0.5 (1)精馏段:

??0×10000.004×1000

==1.33 ??3???1

??012????110.521.02

=0.051()=0.051()=0.0282

??0????10.5816.662

(2)提馏段:

???2

??022????211.1120.75

=0.051()=0.051()=0.0203

??0????20.5931.46⑵板上充气液层阻力 (1)精馏段:

????1

????11.72508===1.91??╱?? ????1?????1.1304?0.2261????1=????1√????1=1.91×√1.02=1.93

由充气系数关联图查得:β1=0.564

23

图4-4充气系数关联图

???1=??1????=0.564×0.07=0.039??

(2)提馏段:

????2

????21.82151===2.01??╱?? ????2?????1.1304?0.2261????2=????2√????2=2.01×√0.75=1.74

由充气系数关联图查得:β2=0.573

???2=??2????=0.573×0.07=0.04??

⑶液体表面张力所造成的阻力 (1)精馏段:

???1=

4??1×0.0014×35.34×0.001

==0.0044

????1×9.81??0816.66×9.81×0.004

???1=???1+???1+???1=0.0282+0.039+0.0044=0.072??

气体通过每层塔板压降:

24

??????1=???1????1??=0.072×816.66×9.81=576.82????

△Pp=576.82Pa<0.7kPa (2)提馏段:

???2=

4??2×0.0014×55.9×0.001

==0.0061

????2×9.81??0931.46×9.81×0.004???2=???2+???2+???2=0.0203+0.04+0.0061=0.066??

气体通过每层塔板压降:

??????2=???2????2??=0.066×931.46×9.81=603.08????

△Pp=603.08Pa<0.7kPa

(2)液面落差

对于筛板塔,液面落差很小,且本设计的塔径和液流量均不大,故可忽略液面落差的影响。

(3)雾沫夹带

???=2.5????=2.5×0.07=0.18??

(1)精馏段:

????1

3.23.25.7×10?6????15.7×10?61.91

=()=()=0.0844????液╱????╱

??1????????35.340.45?0.180.0844(kg液/kg气)<0.1(kg液/kg气) (2)提馏段:

????2

3.23.25.7×10?6????25.7×10?62.01=()=()=0.0629????液╱????╱

??2????????55.90.45?0.180.0629(kg液/kg气)<0.1(kg液/kg气) 故设计液沫夹带量e_v在允许范围内。

(4)漏液

对于筛板塔,漏液点气速的计算

25

(1)精馏段:

=4.4??0√(0.0056+0.13???????1)×(

=6.32??╱??

????1

??0??????1

????1

)=4.4×0.5√(0.0056+0.13×0.07?0.0044)×(

816.661.02

)

筛板稳定系数:

??1=

1.66>1.5 (2)提馏段:

??01??0??????1

=

10.52

=1.66 6.32??0??????2=4.4??0√(0.0056+0.13???????2)×(

????2

=7.19??╱??

????2

)=4.4×0.5√(0.0056+0.13×0.07?0.0061)×(

931.460.75

)

筛板稳定系数:

??2=

1.55>1.5

??02??0??????2

=

11.11

=1.55 7.19介于1.5-2.0之间,故在设计负荷下不会发生明显漏液现象。

(5)液泛

为防止塔内发生液泛,降液管内液层高度H_d<φ(H_T+hW),安全系数φ=0.5 (1)精馏段:

液体通过降液管的压头损失(不设进口堰)

????1=??(????+???1)=0.5×(0.45+0.064)=0.257?? ???1

????120.001192

=0.153()=0.153()=0.0026??

?????011.02×0.009????1=???1+???1+????=0.072+0.0026+0.07=0.1446

0.1446m<0.257m (2)提馏:

????2=??(????+???2)=0.5×(0.45+0.059)=0.254??

26

???2

????220.003062

=0.153()=0.153()=0.0026??

?????021.02×0.023????2=???2+???2+????=0.066+0.0026+0.07=0.1386

0.1386m<0.254m

故在设计负荷下不会液泛。

根据以上塔板的各项流体力学核算,可认为精馏段、提馏段塔径及各工艺尺寸是合适的。

4.5塔板负荷性能图

(1)雾沫夹带线

以ev=0.1kg液/kg气为限,

5.7×10?6????由????=()

????????????

⑴精馏段:

3.2;

????1

????????1

===1.11????1 ?????????1.1304?0.22612323?????

2??????3600????1×0.012

=0.0442()=0.0442()=0.54????13

????1.022

3

???=2.5???=2.5×(???+?????)=2.5×(0.064+0.54????1

?6

)=0.16+1.35????1

3.2

23

5.7×10????=(1.11×

35.34×0.001????2

(0.45?(0.16+1.35????2

23

2))3)=0.1

整理得:????1=1.95?(9.07????1

)

⑵提馏段:

????2=

????????2

==1.11????2

?????????1.1304?0.226127

化工课程设计 - 图文 

??01=⑵提馏段:????11.72508==10.52??╱????00.164??02=????21.82151==11.11??╱????00.1644.4流体力学核算(1)塔板压降1.精馏段⑴干板阻力因为Φ≤15%,????=
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