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半导体物理与器件第四版课后习题答案2

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Chapter 2

Sketch

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Sketch

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Sketch

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From Problem , phase ?2?x???t

= constant Then

2???dxdt???0,?dxdt?????p?????2??? From Problem , phase ?2?x???t

= constant Then

2???dxdt???0,?dxdt????????p??2??? _______________________________________

E?h??hc???hc?E

Gold: E?4.90eV??4.90??1.6?10?19?

J So,

?6.625?10?34??3?1010?????5?4.90??1.6?10?19?2.54?10cm

or

??0.254?m

Cesium: E?1.90eV??1.90??1.6?10?19?J

So,

?3410???6.625?10??3?10??5?1.90??1.6?10?19??6.54?10cm

or

??0.654?m

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h6.625?10?34 (a) p???550?10?9

?1.205?10?27kg-m/s

??p1.2045?10?273m?9.11?10?31?1.32?10m/s or ??1.32?105cm/s

p?h6.625?10?34 (b) ??440?10?9

?1.506?10?27kg-m/s

p1.5057?10?27????1.65?103m9.11?10?31m/s or ??1.65?105cm/s (c) Yes

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(a) (i)

p?2mE?2?9.11?10?31??1.2??1.6?10?19?

?5.915?10?25kg-m/sh6.625?10?34 ??p?5.915?10?25?1.12?10?9m or ??11.2Ao

(ii)p?2?9.11?10?31??12??1.6?10?19? ?1.87?10?24kg-m/s ?34 ??6.625?101.8704?10?3.54?10?10?24m or ??3.54Ao

(iii) p?2?9.11?10?31??120??1.6?10?19? ?5.915?10?24kg-m/s ?34 ??6.625?105.915?10?24?1.12?10?10m or ??1.12Ao

(b)

p?2?1.67?10?27??1.2??1.6?10?19? ?2.532?10?23kg-m/s??6.625?10?34 2.532?1023?2.62?10?11?m or ??0.262Ao

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Eavg?3?2kT??3??2???0.0259??0.03885eV Now

pavg?2mEavg

? ?

?29.11?10?31?0.03885??1.6?10?19?

or

pavg?1.064?10?25kg-m/s Now

??h6.625?10?34p?1.064?10?25?6.225?10?9m or

??62.25Ao

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Ep?h?hcp??

p

Now

Ep2ee?2m and

ph1?h?2e???Ee???e2m???e?? Set Ep?Ee and ?p?10?e Then

22 hc1??h??1??????10h??p2m???e?2m???p? ? which yields

?100hp?2mc Ehchc2mc2 p?E????2mc? p100h100 ?2?9.11?10?31??3?108?2100

?1.64?10?15J ?10.25keV _______________________________________

p?h6.625?10?34(a)??85?10?10

?7.794?10?26 kg-m/s

??p7.m?794?10?2649.11?10?31?8.56?10m/s or ??8.56?106cm/s

E?1m?2?12?9.11?10?31??8.56?1042?2

?3.33?10?21J

or E?3.334?10?211.6?10?19?2.08?10?2eV (b) E?1?9.11?10?31??8?103?22 ?2.915?10?23J

or E?2.915?10?23?1.82?10?41.6?10?19eV p?m???9.11?10?31??8?103? ?7.288?10?27kg-m/s

h6.625?10?35??p?7.288?10?27?9.09?10?8m or ??909Ao

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(a) E?h??hc?6.625?10?348????3?10?1?10?10 ?1.99?10?15J

Now

E?e?V?V?E1.99?10?15 e?1.6?10?19

V?1.24?104V?12.4kV

(b)

p?2mE?2?9.11?10?31??1.99?10?15?

?6.02?10?23kg-m/s

Then

h6.625?10?34??p?6.02?10?23?1.10?10?11m or

??0.11Ao

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?p??1.054?10?34 ?x?10?6 ?1.054?10?28kg-m/s

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(a) (i) ?p?x??

?p?1.054?10?34?2612?10?10?8.783?10kg-m/s (ii)?E?dEd?p2?dp??p?dp?????p ?2m?? ?2p2m??p?p?pm Now p?2mE

?2?9?10?31??16??1.6?10?19? ?2.147?10?24kg-m/s

?2.1466?10?24??8.?26so ?E?783?10?9?10?31

?2.095?10?19J

or ?E?2.095?10?191.6?10?19?1.31eV

(b) (i) ?p?8.783?10?26kg-m/s (ii)p?2?5?10?28??16??1.6?10?19? ?5.06?10?23kg-m/s

?5?23?26 ?E?.06?10??8.783?10?5?10?28

?8.888?10?21J

?E?8.888?10?21 or 1.6?10?19?5.55?10?2eV _______________________________________

?p???x?1.054?10?3410?2?1.054?10?32kg-m/s

p?m??????p1.054?10?32m?1500 ???7?10?36m/s

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(a) ?E?t??

?t?1.054?10?34?0.8??1.6?10?19??8.23?10?16s

??1.054?10?34(b) ?p?x?1.5?10?10 ?7.03?10?25kg-m/s

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(a) If ?1?x,t? and ?2?x,t? are

solutions to

Schrodinger's wave equation, then

??22??1?x,t?2m???1?x,t??x2?V?x??1?x,t??j??t and

??222m???2?x,t??x2?V?x??2?x,t??j???2?x,t??t Adding the two equations, we obtain

??2?22m??x2??1?x,t???2?x,t?? ? ?Vx???1?x,t???2?x,t??

?j???t??1?x,t???2?x,t??

which is Schrodinger's wave equation.

So

?1?x,t???2?x,t? is also a solution.

(b) If ?1?x,t???2?x,t? were a

solution to

Schrodinger's wave equation, then we could write

??2?2 2m??x2??1??2??V?x???1??2? ?j???t??1??2?

which can be written as

??2

?2m???2?2?2?1??1??2??1?x2??2?x2?2?x??x? ?

?V?x???????2??1?1??2??j???1?t??2?t?? Dividing by ?1??2, we find

??2?2m?1??2?21?2?12??1??2??2?2?x??2???x?x?1?x?1?2? ?V?x??j???1??2???1??1?2?t?1?t??

Since ?1 is a solution, then ??22m?1???2?1?x2?V?x??j??1??1?? 11?t Subtracting these last two equations,

we have

??2 ?2m?1?2?22??1??2???2??2?x?1?2?x?x? ?

?j??1??2?? 2?t Since ?2 is also a solution, we have

2 ??22m?1????2?V?x??j??1??2?? 2?x22?t Subtracting these last two equations,

we obtain

??2????2m?2??1?2?V?x??0

1?2?x?x This equation is not necessarily valid, which

means that ?1?2 is, in general, not a solution

to Schrodinger's wave equation. _______________________________________

?3

?A2cos2???x??dx?1?1?2?

A2??xsin??x???3?2?2????1 ?1 A2??3?2????1??2??????1

so A2?12

or A?12

半导体物理与器件第四版课后习题答案2

Chapter2Sketch_______________________________________Sketch_______________________________________Sketch_______
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