实用标准文案
解：
112(ai?bix?ciy)?(21?3x?y)?li(5,4)?2A1313116lj(x,y)?(aj?bjx?cjy)?(?21?4x?3y)?lj(5,4)?2A1313115lm(x,y)?(am?bmx?cmy)?(?6?x?4y)?lm(5,4)?2A131318615Ni?li(2li?1)??;Nj?lj(2j?1)??;Nm?lm(2lm?1)??1691691691204048N1?4ljlm?;N2?4lmli?;N1?4lilj?;1691691690Nj0Nm0N10N20N30??N?N???i?0N0N0N0N0N0Nijm123??li(x,y)????P??PxPyT??1P3P?2??2??18P?183PeT?R?P??N??P???338?3381222A?163?13156bi?yj?ym??3;bj?4;bm??1ci?xm?xj??1;cj??3;cm?4ai?xjym?xmyj?21;aj??2;am??6??T?6P338?63P338?15P338?153P338120P338
1203P33840P338403P33848P338483P??338?5、已知材料的弹性模量E和泊松比?。计算图示四面体ijmp单元的形函数
Ni,Nj,Nm和NP；单元的刚度矩阵中的元素K11和K22。
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2011级南京理工大学有限元理论作业
实用标准文案解：112(ai?bix?ciy)?(21?3x?y)?li(5,4)?2A1313116lj(x,y)?(aj?bjx?cjy)?(?21?4x?3y)?lj(5,4)?2A1313115lm(x,y)?(am?bmx?cmy)?(?6?x?4y)?lm(5,4)?2A131318615Ni?li(2li?1)??;Nj?lj(2
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