for(j=1;j<=50;j++) {
a=(2*PAI/16)*i+(2*PAI/180)*k-1; x=ceil(x0+48*cos(a)); y=ceil(y0+48*sin(a)*B); line(x0,y0,x,y); } }
restorecrtmode(); }
============================================================== 【程序60】题目：画图，综合例子。 #include \#define LEFT 0 #define TOP 0
#define RIGHT 639 #define BOTTOM 479 #define LINES 400
#define MAXCOLOR 15 main() {
int driver,mode,error; int x1,y1; int x2,y2;
int dx1,dy1,dx2,dy2,i=1; int count=0; int color=0; driver=VGA; mode=VGAHI;
initgraph(&driver,&mode,\x1=x2=y1=y2=10; dx1=dy1=2; dx2=dy2=3; while(!kbhit()) {
line(x1,y1,x2,y2); x1+=dx1;y1+=dy1; x2+=dx2;y2+dy2;
if(x1<=LEFT||x1>=RIGHT) dx1=-dx1;
if(y1<=TOP||y1>=BOTTOM) dy1=-dy1;
if(x2<=LEFT||x2>=RIGHT) dx2=-dx2;
if(y2<=TOP||y2>=BOTTOM) dy2=-dy2;
if(++count>LINES) {
setcolor(color);
color=(color>=MAXCOLOR)?0:++color; } }
closegraph(); }
============================================================== 【程序61】题目：打印出杨辉三角形（要求打印出10行如下图） 1
1 1 1 2 1 1 3 3 1 1 4 6 4 1
1 5 10 10 5 1 main() {int i,j;
int a[10][10]; printf(\
for(i=0;i<10;i++)
{a[i][0]=1; a[i][i]=1;} for(i=2;i<10;i++) for(j=1;j a[i][j]=a[i-1][j-1]+a[i-1][j]; for(i=0;i<10;i++) {for(j=0;j<=i;j++) printf(\ printf(\ } } ============================================================== 【程序62】题目：学习putpixel画点。 #include \#include \main() { int i,j,driver=VGA,mode=VGAHI; initgraph(&driver,&mode,\setbkcolor(YELLOW); for(i=50;i<=230;i+=20) for(j=50;j<=230;j++) putpixel(i,j,1); for(j=50;j<=230;j+=20) for(i=50;i<=230;i++) putpixel(i,j,1); } ============================================================== 【程序63】题目：画椭圆ellipse #include \#include \#include \main() { int x=360,y=160,driver=VGA,mode=VGAHI; int num=20,i; int top,bottom; initgraph(&driver,&mode,\top=y-30; bottom=y-30; for(i=0;i ellipse(250,250,0,360,top,bottom); top-=5; bottom+=5; } getch(); } ============================================================== 【程序64】题目：利用ellipse and rectangle 画图。 #include \#include \#include \main() { int driver=VGA,mode=VGAHI; int i,num=15,top=50; int left=20,right=50; initgraph(&driver,&mode,\for(i=0;i ellipse(250,250,0,360,right,left); ellipse(250,250,0,360,20,top); rectangle(20-2*i,20-2*i,10*(i+2),10*(i+2)); right+=5; left+=5; top+=10; } getch(); } ============================================================== 【程序65】题目：一个最优美的图案。 #include \#include \#include \#include \#include \#include \#include \#define MAXPTS 15 #define PI 3.1415926 struct PTS { int x,y; }; double AspectRatio=0.85; void LineToDemo(void) { struct viewporttype vp; struct PTS points[MAXPTS]; int i, j, h, w, xcenter, ycenter; int radius, angle, step; double rads; printf(\getviewsettings( &vp ); h = vp.bottom - vp.top; w = vp.right - vp.left; xcenter = w / 2; /* Determine the center of circle */ ycenter = h / 2; radius = (h - 30) / (AspectRatio * 2); step = 360 / MAXPTS; /* Determine # of increments */ angle = 0; /* Begin at zero degrees */ for( i=0 ; i points[i].y = ycenter - (int)( sin(rads) * radius * AspectRatio ); angle += step; /* Move to next increment */ } circle( xcenter, ycenter, radius ); /* Draw bounding circle */ for( i=0 ; i {int driver,mode; driver=CGA;mode=CGAC0; initgraph(&driver,&mode,\setcolor(3); setbkcolor(GREEN); LineToDemo();}?? ============================================================== 【程序66】 题目：输入3个数a,b,c，按大小顺序输出。 程序分析：利用指针方法。 /*pointer*/ main() { int n1,n2,n3; int *pointer1,*pointer2,*pointer3; printf(\scanf(\pointer1=&n1; pointer2=&n2; pointer3=&n3; if(n1>n2) swap(pointer1,pointer2); if(n1>n3) swap(pointer1,pointer3); if(n2>n3) swap(pointer2,pointer3); printf(\} swap(p1,p2) int *p1,*p2; {int p; p=*p1;*p1=*p2;*p2=p; } ============================================================== 【程序67】题目：输入数组，最大的与第一个元素交换，最小的与最后一个元素交换，输出数组。 main() { int number[10]; input(number); max_min(number); output(number); } input(number) int number[10]; {int i; for(i=0;i<9;i++) scanf(\ scanf(\} max_min(array) int array[10]; {int *max,*min,k,l; int *p,*arr_end; arr_end=array+10; max=min=array; for(p=array+1;p *p=array[0];array[0]=l;l=*p; *p=array[9];array[9]=k;k=*p; return; } output(array) int array[10]; { int *p; for(p=array;p ============================================================== 【程序68】题目：有n个整数，使其前面各数顺序向后移m个位置，最后m个数变成最前面的m个数 main() { int number[20],n,m,i; printf(\scanf(\printf(\scanf(\for(i=0;i scanf(\scanf(\move(number,n,m); for(i=0;i printf(\printf(\} move(array,n,m) int n,m,array[20]; { int *p,array_end; array_end=*(array+n-1); for(p=array+n-1;p>array;p--) *p=*(p-1); *array=array_end; m--; if(m>0) move(array,n,m); } ============================================================== 【程序69】题目：有n个人围成一圈，顺序排号。从第一个人开始报数（从1到3报数），凡报到3的人退出圈子，问最后留下的是原来第几号的那位。 #define nmax 50 main() { int i,k,m,n,num[nmax],*p; printf(\scanf(\p=num; for(i=0;i while(m if(*(p+i)!=0) k++; if(k==3) { *(p+i)=0; k=0; m++; } i++; if(i==n) i=0; } while(*p==0) p++; printf(\} ============================================================== 【程序70】题目：写一个函数，求一个字符串的长度，在main函数中输入字符串，并输出其长度。 main() { int len; char *str[20]; printf(\scanf(\len=length(str); printf(\} length(p) char *p; { int n; n=0; while(*p!='\\0') { n++; p++; } return n; } ============================================================== 【程序71】题目：编写input()和output()函数输入，输出5个学生的数据记录。 #define N 5 struct student { char num[6]; char name[8];
C语言经典程序100题（完整版）
