第1题 集合
1、已知全集U??1,2,3,4,5,6,7,8?集合A??2,3,5,6?集合B??1,3,4,6,7?则集合
A??eUB??( )
A. ?2,5?
B. ?3,6?
C. ?2,5,6?
D. ?2,3,5,6,8?
2、已知集合A={第一象限角},B={锐角},C={小于90?的角},则关系正确的是( ) A. B?AIC
B. BUC?C
C. AüC
D. A?B?C
3、已知集合A??x|x?2?,B???1,0,1,2,3?,则A?B?( )
A.
?0,1?
B.
?0,1,2? C.
??1,0,1?
D. ??1,0,1,2?
4、已知集合 A??x|x?1?,B??x|x?0?则( ) A.AIB??x|x?0?
B.AUB?R C.AUB??x|x?1?
D.AIB??
5、已知集合A??x?N|x?2?,B???1,1?,则AUB?( ) A.?1?
B.??11,,2?
C.??1,0,1,2?
D.?0,1,2?
6、已知集合A??0,1,2?,B??x|x?2n?1,n?A?,则AUB中元素的个数为( ) A.1
B.3
C.4
D.5
7、设集合M??xlog2?x?1??0?,集合N??xx??2?,则M?N?( ) A.?x?2?x?2? B.?xx??2?
C.?xx?2?
D.?x1?x?2?
8、已知集合M??1,2?,N??2,3,4?若P?M?N,则P的子集个数为( )
A.14
B.15
C.16
D.32
9、已知集合A=?x0?x?3?,B??x1?x?2?则AUB?( ) A.?xx?0?
B.?xx?2?
C.?x1?x?3? D.?x0?x?2?
10、设全集U?R,A??x?x?3??x?1??0?,B??xx?2?,则?eUA??B?( ) A.?x1?x?2? B.?x1?x?2? C.?xx?2?
D.?xx?1?
1
11、设全集为R,集合A?x0?x?2,B?xx?1,则AIeRB?( ) A.x0?x?1
??????????B.x0?x?1
2?3???C.x1?x?2
??D.x0?x?2
???12、已知集合M??x?1?x??,N??xlog2?2x?1??0?,则MIeRN?( ) A.??1,1?
B.?,? ?23??12???C.?
D.??1,?
2??1?13、设全集U?R,A=xx?x?3??0,B?xx??1则图中阴影部分表示的集合为( )
????
A.??1,0? B.??3,?1? C.??1,0? D.???,?1?
14、已知全集U?R,集合A??0,1,2,3,4?,B?xx?2,或x?0,则图中阴影部分表示的集合为( )
??
A.?0,1,2? C.?3,4?
B.?1,2? D.?0,3,4?
15、设全集 U?{x?Z|?1?x?5},A??1,2,5?,B?{x?N|?1?x?4},则BI(eUA)?( ) A.?3?
B.?0,3?
C.?0,4?
D.?0,3,4?
2
答案以及解析
1答案及解析: 答案:A
解析:∵全集U??1,2,3,4,5,6,7,8?, 集合A??2,3,5,6?, 集合B??1,3,4,6,7?,
∴eUB??2,5,8?,
则A?eUB??2,5?。 故选:A。
2答案及解析: 答案:B
解析:由题意得BüAIC,故A错误;因为B?C,所以BUC?C,故B正确;A与C互不包含,故C错误;由以上分析可知D错误.
3答案及解析: 答案:C 解析:由
A??x|?1?x?2?,得A?B???1,0,1?,故选C.
4答案及解析: 答案:A
解析:∵A??x|x?1?,B??x|x?0?, 则AIB??x|x?0?,AUB??x|x?1? 故选:A.
5答案及解析: 答案:C
解析:∵集合A??x?N|x?2???0,1,2?,B???1,1?,∴AUB???1,0,1,2?,故选C
6答案及解析: 答案:D
3
解析:由已知可得B?{?1,1,3},所以AUB?{?1,01,,2,3},共有5个元素,故选D.
7答案及解析: 答案:B
解析:M?{x|1?x?2} M?N?{x|x??2}
8答案及解析: 答案:C 解析:集合M??1,2?,N??2,3,4?,则P?MUN??1,2,3,4?,∴P
的子集有24?16个.故答案为:C.
9答案及解析: 答案:D
解析:集合A??x0?x?3?,B??x1?x?2?, 所以AUB??x0?x?3?U?x1?x?2???x0?x?2?, 故选D
10答案及解析: 答案:A
解析:由A中不等式解得:x?1或x?3,即A??xx?1或x?3?, ∴eUA??x1?x?3?, ∵B??xx?2?,
∴?eUA?IB??x1?x?3?, 故选:A.
11答案及解析: 答案:B
解析:∵A??x0,x?2?,B??xx?1?,
∴eRB??xx?1?,
4
∴AI?eRB???x?0?x?1?
故选:B
12答案及解析: 答案:D
解析:∵集合M??x?1?x??,
?1?N??xlog1?2x?1??0???x?x?1?,
?2???2?3?∴eRN=?xx?或x?1?,
∴MI?eRN???x?1?x?????1,?.
2??2??故选:D.
13答案及解析: 答案:B
解析:根据题意,由于U?R,A?xx?x?3??0,B?xx??1那么可知阴影部分表示的为集合A,B得交集,那么结合数轴法可知,集合A?x?3?x?0∴B?xx??1 ,因此交集为??3,?1?,选B
14答案及解析: 答案:A
解析:∵全集U?R,集合A??0,1,2,3,4?,B?xx?2或x?0, ∴图中阴影部分表示的集合为:
?1??1???12????????????AI?CUB???0,1,2,3,4?I?x0?x?2???0,1,2?.
故选:A.
15答案及解析: 答案:B
解析:∵ U???1,0,1,2,3,4,5?,B??0,1,2,3?,∴
e,0,3,4?。∴ BI(eUA???1UA)??0,3?
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2020届高考理数二轮复习常考题型大通关(全国卷):第1题 集合
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