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半导体物理与器件第四版课后习题答案

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Chapter 4

4.1

??Eg ni2?NcN?exp??kT??? ?? ?N?T?3cON?O??300??exp???Eg??? ?kT??

where NcO and N?O are the values at 300 K.

(a) Silicon T(K) kT(eV) n?3i(cm) 200 0.01727 7.68?104 400 0.03453 2.38?1012 600 0.0518 9.74?1014 (b) Germanium (c) GaAs T(K) n33i(cm?) ni(cm?) 200 2.16?1010 1.38 400 8.60?1014 3.28?109 600 3.82?1016 5.72?1012 _______________________________________ 4.2

Plot

_______________________________________ 4.3

(a) n2?N??Eg?icN?exp??kT?? ?? ?5?1011?2??2.8?1019??1.04?1019??3?T??300??

?exp???1.12???0.0259??T300???

2.5?1023??2.912?1038??3?T??300??

?exp????1.12??300????0.0259??T???

By trial and error, T?367.5K

(b)

n2i??5?1012?2?2.5?1025

?3?2.912?1038???T????1.?300?12??300???exp???0.0259??T???

By trial and error, T?417.5K

_______________________________________ 4.4

At T?200K, kT??0.0259???200??300??

?0.017267eV

At T?400K, kT??0.0259???400??300??

?0.034533eV

n2i?400??7.70?1010?217n2i?200???1.40?102?2?3.025?10

??400?3exp??Eg???300????0.034533???3?

?200??300??exp???Eg??0.017267??

?8exp??EgEg??0.017267?0.034533?

?

3.025?1017?8exp?Eg?57.9139?28.9578??

or

?3.025?1017E?g?28.9561??ln????8???38.1714 or Eg?1.318eV

Now ?7.70?1010?23?N?400?coN?o??300??

??x??exp???1.318??0.034533?? 5.929?1021?N?17coN?o?2.370??2.658?10? so NcoN?o?9.41?1037cm?6

_______________________________________ 4.5

???1.10nexp???i?Bn??kT??exp???0.20?? i?A?exp???0.90??kT??kT?? For T?200K, kT?0.017267eV For T?300K, kT?0.0259eV For T?400K, kT?0.034533eV

(a) For T?200K, ? niB?n?exp???0.20????9.325?10?6 i?A??0.017267(b) For T?300K, ? ni?B??0.20??nA??exp??0.0259???4.43?104 i?(c) For T?400K, ? niB?n??exp???0.20??0.034533???3.05?10?3 i?A_______________________________________ 4.6

(a) g?E?E???E?EF??cfFcexp??kT??

?E?E???E?Ec??cexp??kT??

?exp????Ec?EF???kT?? Let E?Ec?x

Then gcfF?xexp??kT??

To find the maximum value: d?gcfF?dx?12x?1/2exp???x??kT??

?1kT?x1/2exp???x??kT???0 which yields

1x1/2 kT2x1/2?kT?x?2 The maximum value occurs at

E?EkTc?2

(b)

g?E???EF?E????1?fF???Eexp??kT??

?E???E??E????Eexp??kT?? ?exp?? ??EF?E????kT?? Let E??E?x

Then g??x???1?fF??xexp??kT??

To find the maximum value ?

dg??1?fF??dx?d?dx??xexp???x??kT??????0 Same as part (a). Maximum occurs at

x?kT2

or

E?EkT??2

_______________________________________ 4.7

E?E????E1?Ec??1cexp

n?E1??kT??n?E?2?Eexp????E

2?Ec??2?Ec?kT?? where

E?4kT and EkT1?Ec2?Ec?2 Then

n?E1?4kT???E1?E2??n?E?2?kTexp??kT?? 2

?22exp???????4?1??2?????22exp??3.5?

or

n?E1?n?E?0.0854

2?_______________________________________ 4.8

Plot

_______________________________________ 4.9

Plot

_______________________________________ 4.10

E3?Fi?Emidgap?4kTln?m*p???m*? n?? Silicon: m**p?0.56mo, mn?1.08mo

EFi?Emidgap??0.0128eV Germanium: m*p?0.37mo,

m*n?0.55mo

EFi?Emidgap??0.0077eV Gallium Arsenide: m*p?0.48mo,

m*n?0.067mo EFi?Emidgap??0.0382eV _______________________________________ 4.11 E1Fi?Emidgap??kT?ln??N??2???Nc??

?12?kT?ln???1.04?1019???2.8?1019????0.4952?kT? T(K) kT(eV) (EFi?Emidgap)(eV) 200 0.01727 ?0.0086 400 0.03453 ?0.0171 600 0.0518 ?0.0257 _______________________________________ 4.12

(a) E3?m*p?Fi?Emidgap?4kTln???*?m

n?? ?3?0.70?4?0.0259?ln??1.21??

??10.63meV

(b) E3?0.75?Fi?Emidgap?4?0.0259?ln??0.080??

??43.47meV

_______________________________________ 4.13

Let gc?E??K?constant Then

? no?gc?E?fF?E?dE

E?c? ?K?1exp???dE

Ec1??E?EF?kT???? ?K?exp????E?EF??Ec?kT??dE Let ??E?EckT so that dE?kT?d?

We can write E?EF??Ec?EF???E?Ec?

so that

半导体物理与器件第四版课后习题答案

Chapter44.1??Egni2?NcN?exp??kT??????N?T?3cON?O??300??exp???Eg????kT??whereNcOandN?Oarethevaluesat300K.(a)SiliconT
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