printf(\ for (i=0;i printf(\ \ printf(\ return 0; } void move(int array[20],int n,int m) {int *p,array_end; array_end=*(array+n-1); for (p=array+n-1;p>array;p--) *p=*(p-1); *array=array_end; m--; if (m>0) move(array,n,m); } 8-5 #include {int i,k,m,n,num[50],*p; printf(\ scanf(\ p=num; for (i=0;i *(p+i)=i+1; i=0; k=0; m=0; while (m if (k==3) {*(p+i)=0; k=0; m++; } i++; if (i==n) i=0; } while(*p==0) p++; printf(\ return 0; } 请浏览后下载,资料供参考,期待您的好评与关注! 8-6 #include {int length(char *p); int len; char str[20]; printf(\ \scanf(\len=length(str); printf(\return 0; } int length(char *p) {int n; n=0; while (*p!='\\0') {n++; p++; } return(n); } 8-7 #include {void copystr(char *,char *,int); int m; char str1[20],str2[20]; printf(\ gets(str1); printf(\ scanf(\ if (strlen(str1) printf(\ else {copystr(str1,str2,m); printf(\ } return 0; 请浏览后下载,资料供参考,期待您的好评与关注! } void copystr(char *p1,char *p2,int m) {int n; n=0; while (n while (*p1!='\\0') {*p2=*p1; p1++; p2++; } *p2='\\0'; } 8-8 #include {int upper=0,lower=0,digit=0,space=0,other=0,i=0; char *p,s[20]; printf(\ \ while ((s[i]=getchar())!='\\n') i++; p=&s[0]; while (*p!='\\n') {if (('A'<=*p) && (*p<='Z')) ++upper; else if (('a'<=*p) && (*p<='z')) ++lower; else if (*p==' ') ++space; else if ((*p<='9') && (*p>='0')) ++digit; else ++other; p++; } printf(\ lower case:%d\ printf(\ space:%d digit:%d other:%d\\n\return 0; } 请浏览后下载,资料供参考,期待您的好评与关注! 8-9 #include {void move(int *pointer); int a[3][3],*p,i; printf(\ for (i=0;i<3;i++) scanf(\ p=&a[0][0]; move(p); printf(\ for (i=0;i<3;i++) printf(\ return 0; } void move(int *pointer) {int i,j,t; for (i=0;i<3;i++) for (j=i;j<3;j++) {t=*(pointer+3*i+j); *(pointer+3*i+j)=*(pointer+3*j+i); *(pointer+3*j+i)=t; } } 8-10-1 #include {void change(int *p); int a[5][5],*p,i,j; printf(\ for (i=0;i<5;i++) for (j=0;j<5;j++) scanf(\ p=&a[0][0]; change(p); printf(\ for (i=0;i<5;i++) {for (j=0;j<5;j++) printf(\ printf(\ } 请浏览后下载,资料供参考,期待您的好评与关注! return 0; } void change(int *p) {int i,j,temp; int *pmax,*pmin; pmax=p; pmin=p; for (i=0;i<5;i++) for (j=i;j<5;j++) {if (*pmax<*(p+5*i+j)) pmax=p+5*i+j; if (*pmin>*(p+5*i+j)) pmin=p+5*i+j; } temp=*(p+12); *(p+12)=*pmax; *pmax=temp; temp=*p; *p=*pmin; *pmin=temp; pmin=p+1; for (i=0;i<5;i++) for (j=0;j<5;j++) if (((p+5*i+j)!=p) && (*pmin>*(p+5*i+j))) pmin=p+5*i+j; temp=*pmin; *pmin=*(p+4); *(p+4)=temp; pmin=p+1; for (i=0;i<5;i++) for (j=0;j<5;j++) if (((p+5*i+j)!=(p+4))&&((p+5*i+j)!=p)&&(*pmin>*(p+5*i+j)))pmin=p+5*i+j; temp=*pmin; *pmin=*(p+20); *(p+20)=temp; pmin=p+1; for (i=0;i<5;i++) for (j=0;j<5;j++) if (((p+5*i+j)!=p) && ((p+5*i+j)!=(p+4)) && ((p+5*i+j)!=(p+20)) (*pmin>*(p+5*i+j))) pmin=p+5*i+j; temp=*pmin; *pmin=*(p+24); *(p+24)=temp; } 请浏览后下载,资料供参考,期待您的好评与关注! &&
《C语言程序设计》课后习题答案(第四版)谭浩强
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