完整word版,《C语言程序设计》课后习题答案(第四版)谭浩强

5-6

#include int main()

{double s=0,t=1; int n;

for (n=1;n<=20;n++) {

t=t*n; s=s+t; }

printf(\ return 0; } 5-7

#include int main() {

int n1=100,n2=50,n3=10; double k,s1=0,s2=0,s3=0;

for (k=1;k<=n1;k++) /*计算1到100的和*/ {s1=s1+k;}

for (k=1;k<=n2;k++) /*计算1到50各数的平方和*/ {s2=s2+k*k;}

for (k=1;k<=n3;k++) /*计算1到10的各倒数和*/ {s3=s3+1/k;}

printf(\ return 0; } 5-8

#include int main() {

int i,j,k,n;

printf(\ for (n=100;n<1000;n++) {

i=n/100; j=n/10-i*10;

k=n;

if (n==i*i*i + j*j*j + k*k*k) printf(\ }

printf(\ return 0; } 5-10

#include int main() {

int i,n=20;

double a=2,b=1,s=0,t; for (i=1;i<=n;i++) {

s=s+a/b; t=a, a=a+b, b=t; }

printf(\ return 0; } 5-11

#include int main() {

double sn=100,hn=sn/2; int n;

for (n=2;n<=10;n++) {

sn=sn+2*hn; /*第n次落地时共经过的米数*/ hn=hn/2; /*第n次反跳高度*/ }

printf(\第10次落地时共经过%f米\\n\ printf(\第10次反弹%f米\\n\ return 0; } 5-12

#include int main() {

int day,x1,x2; day=9;

x2=1;

while(day>0)

{x1=(x2+1)*2; /*第1天的桃子数是第2天桃子数加1后的2倍.*/ x2=x1; day--; }

printf(\ return 0; } 5-13

#include #include int main() {

float a,x0,x1;

printf(\ scanf(\ x0=a/2;

x1=(x0+a/x0)/2; do

{x0=x1;

x1=(x0+a/x0)/2;

}while(fabs(x0-x1)>=1e-5);

printf(\ is %8.5f\\n\ return 0; } 5-15

#include #include int main()

{float x0,x1,x2,fx0,fx1,fx2; do

{printf(\ scanf(\ fx1=x1*((2*x1-4)*x1+3)-6; fx2=x2*((2*x2-4)*x2+3)-6; }while(fx1*fx2>0); do

{x0=(x1+x2)/2;

fx0=x0*((2*x0-4)*x0+3)-6; if ((fx0*fx1)<0) {x2=x0; fx2=fx0; }

else {x1=x0; fx1=fx0; }

}while(fabs (fx0)>=1e-5); printf(\ return 0; } 5-16

#include int main() {int i,j,k;

for (i=0;i<=3;i++) {for (j=0;j<=2-i;j++) printf(\

for (k=0;k<=2*i;k++) printf(\ printf(\ }

for (i=0;i<=2;i++) {for (j=0;j<=i;j++) printf(\

for (k=0;k<=4-2*i;k++) printf(\ printf(\ }

return 0; } 6-1

#include #include int main()

{int i,j,n,a[101];

for (i=1;i<=100;i++) a[i]=i; a[1]=0;

for (i=2;i

printf(\

for (i=2,n=0;i<=100;i++) { if(a[i]!=0) {printf(\ n++; }

if(n==10)

{printf(\ n=0; } }

printf(\ return 0; } 6-2

#include int main()

{int i,j,min,temp,a[11]; printf(\ for (i=1;i<=10;i++) {printf(\ scanf(\ }

printf(\

printf(\ for (i=1;i<=10;i++) printf(\ printf(\

for (i=1;i<=9;i++) {min=i;

for (j=i+1;j<=10;j++) if (a[min]>a[j]) min=j; temp=a[i]; a[i]=a[min]; a[min]=temp; }

printf(\ for (i=1;i<=10;i++) printf(\ printf(\ return 0; } 6-3

#include